Contents
- search2.py
- search_compare.py
- search_divide.py
- search.py
search2.py 1/4
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# Demonstrate implementations of the linear and binary search
# techniques.
# Sara Sprenkle
# represents that binarySearch did not find the key
NOT_FOUND=-1
def main():
integers = range(1,20,2)
print("The list to search: ", integers)
print()
findMeList = [1, 4, 15, 16, 17]
for key in findMeList:
print("Search for", key)
print("Linear: Found?", linearSearch(integers, key))
# binarySearch returns the position the number was found, or -1 if it was
# not found. Translate the result from binarySearch to a True or False
pos = binarySearch(integers, key)
binFound = pos != NOT_FOUND
print("Binary: Found?", binFound)
print()
def linearSearch(searchlist, key):
"Returns true iff key is in the list of integers searchlist"
for elem in searchlist:
if elem == key:
return True
return False
def binarySearch(searchlist, key):
""" Returns the position where key (an int) is found in the list of sorted
integers searchlist or -1 if key is not in the list. """
low = 0
high = len(searchlist)-1
while low <= high:
mid = (low+high)//2
valueAtMid = searchlist[mid]
if valueAtMid == key:
return mid
if valueAtMid < key: # search upper half
low = mid+1
else: # search lower half
high = mid-1
return NOT_FOUND
main()
search_compare.py 2/4
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# Compare the linear and binary searching techniques by the number of
# comparisons.
# by Sara Sprenkle
def main():
print("This program helps us to empirically compare search strategies")
print()
# The keys I want to search for in a list
#keys = [1, 4, 13, 19, 125, 126, 127]
keys = [1, 4, 13, 19, 125, 126, 127, 19997, 19998, 19999]
NUM_ENTRIES = 10000
# the list of integers that I'm searching (odd numbers)
integers = list(range(1,NUM_ENTRIES*2,2))
#print integers
print("Creating list of size", NUM_ENTRIES*2, "starting at 1 and incrementing by 2")
print()
print("%6s|%14s" % ("","# Comparisons"))
print("%6s| %6s %6s" % ("KEY", "LIN", "BIN"))
print("-"* 24)
total_lin_comp = 0.0
total_bin_comp = 0.0
for key in keys:
lin_comp = linearSearch(integers,key)
bin_comp = binarySearch(integers,key)
print("%6d| %6d %6d" % (key, lin_comp, bin_comp))
# update the total number of comparisons
total_lin_comp += lin_comp
total_bin_comp += bin_comp
print()
print("ON AVERAGE...")
print("-"*50)
print()
print("The average number of comparisons per search for")
print("\tlinear search was", total_lin_comp/len(keys))
print("\tbinary search was", total_bin_comp/len(keys))
print()
print("Disclaimer: May not be a completely fair comparison but gives us an idea.")
# Return the number of comparisons required to find the key.
def linearSearch(searchlist, key):
numChecks = 0
for elem in searchlist:
numChecks += 1
if elem == key:
return numChecks
return numChecks
# Return the number of comparisons required to find the key
def binarySearch(searchlist, key):
low = 0
high = len(searchlist)-1
numChecks = 0
while low <= high:
mid = (low+high)//2
numChecks+= 2 # while comparison, next if comparison
if searchlist[mid] == key:
return numChecks
numChecks+=1
if searchlist[mid] < key:
low = mid+1
else:
high = mid-1
return numChecks
main()
search_divide.py 3/4
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# Binary search, dividing list in half
# Sara Sprenkle
# represents that binarySearch did not find the key
NOT_FOUND=-1
def main():
integers = range(1,20,2)
print("The list to search: ", integers)
print()
findMeList = [1, 4, 15, 16, 17]
for key in findMeList:
print("Search for", key)
# binarySearch returns the position the number was found, or -1 if it was
# not found. Translate the result from binarySearch to a True or False
pos = altBinarySearch(integers, key)
binFound = pos != NOT_FOUND
print("Binary: Found?", binFound)
print()
def altBinarySearch(searchlist, key):
"""Literally divide the list in half. Issues: creates multiple lists.
Each call to the function requires another list (of half the size of
the original)."""
# ran out of elements in the list
if len(searchlist) == 0:
return NOT_FOUND
low = 0
high = len(searchlist)-1
mid = (low+high)/2
valueAtMid = searchlist[mid]
if valueAtMid == key:
return mid
if low == high:
return NOT_FOUND
if searchlist[mid] < key: # search upper half
return altBinarySearch(searchlist[mid+1:], key)
else: # search lower half
return altBinarySearch(searchlist[:mid], key)
main()
search.py 4/4
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# Demonstrate implementation of the linear search technique.
# Sara Sprenkle
def main():
integers = range(1, 20, 2)
print("The list we are searching: ", integers)
print()
findMeList = [1, 4, 15, 16, 17]
for key in findMeList:
print("Search for", key)
print("Linear: Found?", linearSearch(integers, key))
print()
def linearSearch(searchlist, key):
for elem in searchlist:
if elem == key:
return True
return False
main()
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